TSTP Solution File: SEV432^1 by cocATP---0.2.0

View Problem - Process Solution

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% File     : cocATP---0.2.0
% Problem  : SEV432^1 : TPTP v6.1.0. Released v5.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p

% Computer : n113.star.cs.uiowa.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory   : 32286.75MB
% OS       : Linux 2.6.32-431.20.3.el6.x86_64
% CPULimit : 300s
% DateTime : Thu Jul 17 13:34:11 EDT 2014

% Result   : Theorem 0.45s
% Output   : Proof 0.45s
% Verified : 
% SZS Type : None (Parsing solution fails)
% Syntax   : Number of formulae    : 0

% Comments : 
%------------------------------------------------------------------------------
%----ERROR: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% % Problem  : SEV432^1 : TPTP v6.1.0. Released v5.2.0.
% % Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% % Computer : n113.star.cs.uiowa.edu
% % Model    : x86_64 x86_64
% % CPU      : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% % Memory   : 32286.75MB
% % OS       : Linux 2.6.32-431.20.3.el6.x86_64
% % CPULimit : 300
% % DateTime : Thu Jul 17 09:13:16 CDT 2014
% % CPUTime  : 0.45 
% Python 2.7.5
% Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/']
% FOF formula (<kernel.Constant object at 0x1259f80>, <kernel.Type object at 0x12595f0>) of role type named a
% Using role type
% Declaring a:Type
% FOF formula (<kernel.Constant object at 0x14a0908>, <kernel.Type object at 0x1259cf8>) of role type named b
% Using role type
% Declaring b:Type
% FOF formula (<kernel.Constant object at 0x1259b90>, <kernel.DependentProduct object at 0x12594d0>) of role type named f
% Using role type
% Declaring f:(a->b)
% FOF formula (forall (Y:b), ((ex a) (fun (X:a)=> (((eq b) (f X)) Y)))) of role axiom named fsurj
% A new axiom: (forall (Y:b), ((ex a) (fun (X:a)=> (((eq b) (f X)) Y))))
% FOF formula ((ex (b->a)) (fun (G:(b->a))=> (forall (X:b), (((eq b) (f (G X))) X)))) of role conjecture named invexists
% Conjecture to prove = ((ex (b->a)) (fun (G:(b->a))=> (forall (X:b), (((eq b) (f (G X))) X)))):Prop
% Parameter a_DUMMY:a.
% Parameter b_DUMMY:b.
% We need to prove ['((ex (b->a)) (fun (G:(b->a))=> (forall (X:b), (((eq b) (f (G X))) X))))']
% Parameter a:Type.
% Parameter b:Type.
% Parameter f:(a->b).
% Axiom fsurj:(forall (Y:b), ((ex a) (fun (X:a)=> (((eq b) (f X)) Y)))).
% Trying to prove ((ex (b->a)) (fun (G:(b->a))=> (forall (X:b), (((eq b) (f (G X))) X))))
% Found fsurj:(forall (Y:b), ((ex a) (fun (X:a)=> (((eq b) (f X)) Y))))
% Found fsurj as proof of (forall (x:b), ((ex a) (fun (y:a)=> (((eq b) (f y)) x))))
% Found (choice000 fsurj) as proof of ((ex (b->a)) (fun (G:(b->a))=> (forall (X:b), (((eq b) (f (G X))) X))))
% Found ((choice00 (fun (x3:b) (x20:a)=> (((eq b) (f x20)) x3))) fsurj) as proof of ((ex (b->a)) (fun (G:(b->a))=> (forall (X:b), (((eq b) (f (G X))) X))))
% Found (((choice0 a) (fun (x3:b) (x20:a)=> (((eq b) (f x20)) x3))) fsurj) as proof of ((ex (b->a)) (fun (G:(b->a))=> (forall (X:b), (((eq b) (f (G X))) X))))
% Found ((((choice b) a) (fun (x3:b) (x20:a)=> (((eq b) (f x20)) x3))) fsurj) as proof of ((ex (b->a)) (fun (G:(b->a))=> (forall (X:b), (((eq b) (f (G X))) X))))
% Found ((((choice b) a) (fun (x3:b) (x20:a)=> (((eq b) (f x20)) x3))) fsurj) as proof of ((ex (b->a)) (fun (G:(b->a))=> (forall (X:b), (((eq b) (f (G X))) X))))
% Got proof ((((choice b) a) (fun (x3:b) (x20:a)=> (((eq b) (f x20)) x3))) fsurj)
% Time elapsed = 0.142607s
% node=31 cost=129.000000 depth=5
% ::::::::::::::::::::::
% % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p
% % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
% ((((choice b) a) (fun (x3:b) (x20:a)=> (((eq b) (f x20)) x3))) fsurj)
% % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
% EOF
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